1.

) A water tap A takes 7 minutes more than water tap B for filling up a tank with water.The tap A takes 16 minutes more than the time taken by both the taps together to fillthe tank. Find the time each tap alone would take to fill the tank.

Answer»

Let the Water tap B takes the time to fill the tank = y minutes

Now according o 1st condition

The Water tap A takes the time to fill the tank = (y + 7) minutes

Also according to second condition

Time taken by Tap A + 16 = Time taken by Both the taps

y + 7 + 16 = y + ( y + 7 )

y + 23 = 2 y + 7

Rearranging the above equation, we get

2 y + 7 = y + 23

2 y - y = 23 - 7

y = 16

So Water tap B takes the time to fill the tank = 16 minutes

And

Water tap A takes the time to fill the tank = 16 + 7 = 23 minutes

So Tap B alone takes 16 minutes and Tap A alone takes 23 minutes to fill the tank.

srry but the answer given in the answer sheet is this



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