InterviewSolution
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) A water tap A takes 7 minutes more than water tap B for filling up a tank with water.The tap A takes 16 minutes more than the time taken by both the taps together to fillthe tank. Find the time each tap alone would take to fill the tank. |
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Answer» Let the Water tap B takes the time to fill the tank = y minutes Now according o 1st condition The Water tap A takes the time to fill the tank = (y + 7) minutes Also according to second condition Time taken by Tap A + 16 = Time taken by Both the taps y + 7 + 16 = y + ( y + 7 ) y + 23 = 2 y + 7 Rearranging the above equation, we get 2 y + 7 = y + 23 2 y - y = 23 - 7 y = 16 So Water tap B takes the time to fill the tank = 16 minutes And Water tap A takes the time to fill the tank = 16 + 7 = 23 minutes So Tap B alone takes 16 minutes and Tap A alone takes 23 minutes to fill the tank. srry but the answer given in the answer sheet is this |
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