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A wave equation which gives the displacement along the y-direction is given by `y = 10^(-4) sin(60t + 2x)` where `x and y` are in meters and `t` is time in seconds. This represents a waveA. travelling with a velocity of `30 m//s` in the negative x-direction.B. of wavelength `pi m`C. of frequency `30//pi Hz`D. of amplitude `10^-4 m` travelling along the negative x-direction. |
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Answer» Correct Answer - A::B::C::D `y = 10^(-4) sin (60 t + 2 x)`. Comparing the given equation with the stansard wave equation travelling in negative x-direction, `y = a sin(omega t + kx)` We get amplitude `a = 10^(-4) m` Also `omega = 60` `:. 2 pi f = 60 rArr f = (30)/(pi) Hz` Also, `k = 2` `rArr (2 pi)/(lamda) = 2 rArr lamda = pi m` We know that `v = f lamda = (30)/(pi) xx pi = 30 m//s`. |
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