1.

A wave of frequency 500 Hz has a velocity 300 m/s. The distance between two nearest points which are 60^(@) out of phase , is ………… .

Answer»

0.2 m
0.1 m
0.4 m
0.5 m

Solution :0.1 m
`LAMBDA = (300)/(500) = 0.6` m
`Delta X = (lambda)/(2pi) * Delta phi = (0.6)/(2pi) * (pi)/(3) = 0.1 ` m


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