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A wave pulse is generated at the bottom of a uniform string (of mass `m` and length `l`) Suspended from ceiling and supporting a block (of mass `m`) as shown. A. Acceleration of the wave pulse is `g/2`B. Time taken by the wave pulse to travel from botom to ceiling is `((sqrt(2)+1).2)sqrt(l/g)`C. Speed of the wave at bottom of string is `sqrt(gl)`D. Speed of the wave as it is just about to strike the ceiling is`sqrt(2gl)` |
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Answer» Correct Answer - A::C::D At a distance `x` from the bottom, `V=sqrt(T/(mu))=sqrt((mg+(mgx)/l)/(ml))=sqrt(g(l+x))` `impliesa=(V.dV)/(dx)=g/2` Time of motion `=g/2 l/(V_("average"))=(2l)/(sqrt(gl)+sqrt(2gl))` `=2/((sqrt(2)+1))sqrt(l/g)` |
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