A wave representing by the equation `y = a cos(kx - omegat)` is suerposed with another wave to form a stationary wave such that point `x = 0` is a node. The equation for the other wave isA. ` a sin ( kx + omega t)`B. ` - a cos ( kx - omega t)`C. ` - a cos (k x + omega t)`D. `- a sin ( kx - omega t)`

A wave representing by the equation `y = a cos(kx - omegat)` is suerpo

1.	A wave representing by the equation `y = a cos(kx - omegat)` is suerposed with another wave to form a stationary wave such that point `x = 0` is a node. The equation for the other wave isA. ` a sin ( kx + omega t)`B. ` - a cos ( kx - omega t)`C. ` - a cos (k x + omega t)`D. `- a sin ( kx - omega t)`
Answer» Correct Answer - C Since the point ` x = 0` is a node and reflectiion is taking place from point ` x = 0` . This means that reflection must be taking place from the fixed end and hence the reflected ray must suffer an additional phase change of `pi` or a path change of `lambda//2`. So , If `y_("incident") = a cos (kx - omega t)` , then `y _("reflected") = -a cos (omega t + kx)`

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