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InterviewSolution
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A weak acid HX has the dissociation constant `1xx10^(-5)M`. It forms a salt NaX on reaction with alkali. The degree of hydrolysis of 0.1 M solution of NaX isA. `0.0001%`B. `0.01%`C. `0.1%`D. `0.15%` |
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Answer» Correct Answer - B Hydrolysis reaction is `X^(-) + H_(2)O hArr HX+OH^(-)` For a salt of weak acid with strong base, `K_(h)=(K_(w))/(K_(a))=ch^(2)` `:. (10^(-14))/(10^(-5))=0.1xxh^(2) or h^(2) = 10^(-8) or h = 10^(-4)` % hydrolysis `= 10^(-4) xx 100 = 10^(-2) = 0.01` |
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