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A weak monobune add 12% dissociated in 0.05 M solution, what percent dissociation in 0 15 X solution. |
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Answer» Dissociation CONSTANT of ACID K a =Cα 2 =0.01×(0.05) 2 =2.5×10 −5 K a =Cα 2 2.5×10 −5 =0.05×α 2 α=0.0223We know that, α= ∧ m∞ ∧ MC 0.0223= 4×10 −2 ∧ mc ∧ mc =8.92×10 −4 ohm −1 cm 2 MOL −1 |
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