1.

A wedge is moving rightwards on which a block of mass 10kg is placed on it. Friction coefficient between the wedge and the block is 0.8.[ takes g=10m//s^(2)]. Select correct alternative (s) among the following options.

Answer»

If WEDGE is moving with constant velocity then friction ACTING on block is `64N`.
If wedge is moving with constant velocity then acceleration of block is zero.
If wedge is moving with `vec(a)=2(hat(i))m//s^(2)` then friction acting on block is `44N`
If wedge is moving with `vec(a)=10(hat(i))m//s^(2)` then friction is `20N`, DOWNWARD on the wedge along the inclined.

Solution :`(A,B)` If moving with constant velocity then `a=0` so friction AVAILABLE `=mumgcostheta`
`=(0.8)(10)(10)(4//5)=64N`.

but `mgsintheta=60N`
so required friction is `60N`.
So net force is zero .
`(C ) a=2hat (i) f=mg sin 37^(#)-m a cos 37^(@)=44N`
`(D) f=mg sin 37^(@)-ma cos 37^(@)=-20N`


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