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A weight mg is suspended from the middle of a rope whose ends are at the same level. The rope is no longer horizontal. What is the minimum tension required to completely straighten the rope is |
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Answer» Solution :From the diagram `2T sin theta = MG` `T = (mg)/(2 sin theta)` The rope will be straight when `theta = 0` `T = (mg)/(2 sin 0^(@)) = ALPHA` The tension REQUIRED to completely STRAIGHTEN the rope is INFINITY.
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