1.

A weight mg is suspended from the middle of a rope whose ends are at the same level. The rope is no longer horizontal. What is the minimum tension required to completely straighten the rope is

Answer»

Solution :From the diagram
`2T sin theta = MG`
`T = (mg)/(2 sin theta)`
The rope will be straight when `theta = 0`
`T = (mg)/(2 sin 0^(@)) = ALPHA`
The tension REQUIRED to completely STRAIGHTEN the rope is INFINITY.


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