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A well of radius 5.6 m and depth 20 m is dug in a rectangular field of dimcnsions150 m Ă 70 m and the earth dug out from it is evenly spread on the remaining part ofthe field. Find the height by which the field is raised. |
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Answer» Area of the well=2*pi*(5.6)^2 cm2=197.12 m2Area of the rectangular field=150*70 cm2=10500 m2Volume of the mud dug out=Area of the well *depth of the well = 197.12*20 m3=3942.4m3Area of the remaining field=10500-197.12 m2=10302.88 m2let the height by which the field is raised be h m.B.T.P, 10302.88*h=3942.4or, h=0.342 m |
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