1.

A wellof diameter 3 m is dug 14 m deep. The earth taken out of it has been spread evenlyalt around it in the shape of a circular ring of width 4 m to form an embankment. Find theheight of the embankment.

Answer»

Height of the well = 14 mDiameter of the well = 3 mSo, Radius of the well = 3/2 mVolume of the earth taken out of the well=πr²h= 22/7*(3/2)²*14= 99 cu mOuter radius of the embankment = R = (3/2 + 4)m = 11/2 mArea of embankment = outer area - inner area⇒ = πR² -πr²= 22/7*[(11/2)² - (3/2)²]= 22/7*[(121/4) -(9/4)]= 22/7× 112/4= 88 m²Height of the embankment = Volume/Area= 99/88Height of the embankment = 1.125 m



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