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A wheel has angular acceleration of `3.0 rad//s^2` and an initial angular speed of `2.00 rad//s`. In a tine of `2 s` it has rotated through an angle (in radian) ofA. 6B. 10C. 12D. 4 |
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Answer» Correct Answer - B (b) Using `theta = omega_0 t + (1)/(2) prop t^2` Given, `prop = 3.0 rad//s^2, omega_0 = 2.0 rad//s^2, omega_0 = 2.0 rad//s, t = 2 s` Hence, `theta = 2 xx 2 + (1)/(2) xx 3 xx (2)^2` or `theta = 4 + 6 = 10 rad. |
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