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A wheel has mass of the rim 1 kg, having 50 spokes each of mass 5g. The radius of the wheel is 40 cm. The moment of inertia isA. 0.273 kg `m^(2)`B. 1.73 kg `m^(2)`C. 0173 kg `m^(2)`D. 2.73 kg `m^(2)` |
Answer» c) l =` mr^(2) + 50 (ml^(2))/3` `= 1 xx (0.4)^(2) + (50(5 xx 10^(-3))(0.4)^(2))/3` `0.16(1.083) =0.173kgm^(2)` |
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