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A wheel of 1 m radius completes half rotation on horizontal path. Magnitude of displacement form the point of contact with path initially is……… |
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Answer» `2pi` If wheel completes 1 ROTATION, that HORIZONTAL distance is `2pi r.` Here, it completes half rotation. Hence distance covered on horizontal path `= pir = OP` and OQ =2R. From figure `PQ ^(2) =PO^(2) + OQ^(2)` `x^(2) = (pir) ^(2) + (2r)^(2) ` `x=1 sqrt (pi ^(2) +4) [because r =1m]` |
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