1.

A wheel of 1 m radius completes half rotation on horizontal path. Magnitude of displacement form the point of contact with path initially is………

Answer»

`2pi`
`pi`
`SQRT(pi^(2) + 4)`
`2`

Solution :
If wheel completes 1 ROTATION, that HORIZONTAL distance is `2pi r.`
Here, it completes half rotation. Hence distance covered on horizontal path `= pir = OP` and OQ =2R.
From figure `PQ ^(2) =PO^(2) + OQ^(2)`
`x^(2) = (pir) ^(2) + (2r)^(2) `
`x=1 sqrt (pi ^(2) +4) [because r =1m]`


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