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A wheel of mass 40 kg and radius of gyration 0.5 m comes to rest from a speed of 180 rpm in 30 s assuming that the retardation is uniform then the value of the retarding torque, in Nm will beA. `1 pi`B. `3 pi`C. `2 pi`D. `4 pi` |
Answer» Correct Answer - C `tau = I alpha = M k^(2) alpha`. |
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