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A wheel of moment of inertia `5xx10^(-3) kg m^(2)` is making 20 revolutions per second. If it is stopped in 20 s, then its angular retardation would beA. `pi rad //s^(2)`B. `4pi rad//s^(2)`C. `2pi rad//s^(2)`D. `8pi rad //s^(2)` |
Answer» Correct Answer - C `alpha = (omega_(2)-omega_(1))/(t)=(2pi(n_(2)-n_(1)))/(t)=(2pi(0-20))/(t)=2pi` |
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