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A wheel of radius R rolls on the ground with a uniform velocity v. The relative acceleration of topmost point of the wheel with respect to the bottommost point is:A. `(v^(2))/R`B. `(2v^(2))/R`C. `(v^(2))/(2R)`D. `(4v^(2))/R` |
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Answer» Correct Answer - 2 `omega=v/R, a =omega^(2) r =(v/R)^(2) .2R=(2v^(2))/R` |
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