1.

A wheel rotates around a stationary axis so that rotation angle thetavaries as theta= pt^(2) where p=0.2"rad"//"sec"^(2) The total acceleration (a) of the point A at the rim at the moment t = 2.55sec. If linear velocity of the point (A) at this moment is V = 0.65m//sec is

Answer»

`0. 7 m//sec^(2)`
`0.6 m//sec^(2)`
`0.5 m//sec^(2)`
`0.4 m//sec^(2)`

ANSWER :A


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