A wheel rotates with a constant acceleration of 2.0 rad/s^(2). If the wheel starts from rest, the number of revolutions it makes in first ten seconds is

A wheel rotates with a constant acceleration of 2.0 rad/s^(2). If the

1.	A wheel rotates with a constant acceleration of 2.0 rad/s^(2). If the wheel starts from rest, the number of revolutions it makes in first ten seconds is
Answer» 8 16 24 32 Solution :`THETA= omega_(0) t + (1)/(2) alpha t^(2) = 0 + (1)/(2) xx 2 xx 10^(2) = 100` radian No. of revolutions = `(theta)/(2 PI) = (100)/(2pi) = 16`