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a) When a relation R on a set A is said to be reflexiveb) Show that ƒ : [-1, 1] → R given by f(x)= \(\frac{x}{x+2}\) is one-one |
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Answer» a) (a,a) ∈ R, ∀a ∈ A b) f(x1) = f(x2) ⇒ \(\frac{x_1}{x_1 +2}\) = \(\frac{x_2}{x_2 + 1}\) ⇒ x1x2 + 2x1 = x1x2 + 2x2 ⇒ x1 = x2 Hence one - one |
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