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A whistle emitting a sound of frequency `440 H`z is tied to string of `1.5 m` length and rotated with an angular velocity of `20 rad//sec` in the horizontal plane. Then the range of frequencies heard by an observer stationed at a large distance from the whistle will `(v=330 m//s)` |
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Answer» `v_S=romega=1.5xx20=30(m)/(s)` `n_(min)=(v)/(v+v_S)n=(330)/(330+30)xx440Hz=403Hz` `n_(max)=(330)/(330-30)xx440=484Hz` |
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