(a) Why are haloarenes less reactive than haloalkanes? Explain. (b) Predict the alkenes that would be formed by dehydrohalogenation of the following halides with sodium ethoxide in ethanol and predict the major alkene: (i) 2-Chloro-2-methylbutane (ii) 3-bromo-2, 2, 3-trimethylpentane (c) How is chlorobenzene prepared from benzenediazonium chloride?

(a) Why are haloarenes less reactive than haloalkanes? Explain. (b) P

1.	(a) Why are haloarenes less reactive than haloalkanes? Explain. (b) Predict the alkenes that would be formed by dehydrohalogenation of the following halides with sodium ethoxide in ethanol and predict the major alkene: (i) 2-Chloro-2-methylbutane (ii) 3-bromo-2, 2, 3-trimethylpentane (c) How is chlorobenzene prepared from benzenediazonium chloride?
Answer» SOLUTION :(a) `RB^(+) gt K^(+) gt Na^(+) gt Li^(+)` because of lesser hydration of ion as size increases. In other WORDS, hydrated radii of ions decrease as `Li^(+), Na^(+), K^(+), Rb^(+)`. (c) POTASSIUM carbonate cannot be prepared by Solvay process because potassium bicarbonate being more SOLUBLE than sodium bicarbonate does not get precipitated when `CO_(2)` is passed through a concentrated solution of KCl saturated with `NH_(3)`.