A wire 5 m long and cross section 10^(-4)m^(2) is fixed at one end and a mass of 1200 kg is hung from the other end. Find the elongation (y=0.98xx10^(11) N//m^(2))

A wire 5 m long and cross section 10^(-4)m^(2) is fixed at one end and

1.	A wire 5 m long and cross section 10^(-4)m^(2) is fixed at one end and a mass of 1200 kg is hung from the other end. Find the elongation (y=0.98xx10^(11) N//m^(2))
Answer» Solution :`Y=(MGL)/(pir^(2)(DELTAL))=(Mgl)/(A(Deltal))=(1200xx9.8xx5)/(10^(-4)XX(Deltal))=0.98xx10^(11)` `:.Deltal=6xx10^(-3)m=6 MM` `:.` elongation =6 mm