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InterviewSolution
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A wire `50 cm` long and `0.12mm` diameter has a resistance of `4.0 Omega` find the resistance of another wire of the same material whose length is `1.5m` and diameter is `0.15 mm` |
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Answer» Correct Answer - `1.92 Omega` Here, `l = 0.50 m, D = 0.12 xx 10^(-3)m, R = 4.0 Omega` `l_(1) = 1.5m,D_(1) = 0.15 xx 10^(-3)m , R_(1) = ?` `R = (rhol)/(pi D^(2)//4) or R prop (l)/(D^(2))` `:. (R_(1))/(R) = (l_(1))/(l) xx (D^(2))/(D_(1)^(2)) = (1.5)/(0.5) xx ((0.2 xx 10^(-3))^(2))/((0.15 xx 10^(-3))^(2)) = 1.92 Omega` |
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