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A wire carries a current of 0.1A for 20sec of the potential diff bet'n the two ends the wire is 10v find the work done? |
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Answer» 20 JExplanation:GIVEN:-A = 0.1t = 20sV = 10W = ?A=Q/t0.1 = Q/20Q = 20 × 0.1Q = 2 CNOW,V = W/Q10 = W / 2W = 20 J |
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