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A wire carries a current of 0.5A, when a potential differnece of 1.5 V is applied across it. What is its conductance ? If the wire is of length 3 m and area of cross-section `5.4 mm^(2)`, calculate its conductivity. |
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Answer» Here, `I=0.5 A , V=1.5 V, l=3 m`, `A = 5.4 mm^(2) = 5.4 xx 10^(-6) m^(2)` Now, resistance, `R=V/I=1.5/0.5 =3 Omega` Conduction, `G=1/R=1/3=0.33 S` Electrical conductivity, `sigma=1/rho =(l)/(RA)` `=3/( 3xx 5.4 xx 10^(-6))=1.85 xx 10^(5) Sm^(-1)` |
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