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A wire carries a current of 0.5A, when a potential differnece of 1.5 V is applied across it. What is its conductance ? If the wire is of length 3 m and area of cross-section `5.4 mm^(2)`, calculate its conductivity.

Answer» Here, `I=0.5 A , V=1.5 V, l=3 m`,
`A = 5.4 mm^(2) = 5.4 xx 10^(-6) m^(2)`
Now, resistance, `R=V/I=1.5/0.5 =3 Omega`
Conduction, `G=1/R=1/3=0.33 S`
Electrical conductivity, `sigma=1/rho =(l)/(RA)`
`=3/( 3xx 5.4 xx 10^(-6))=1.85 xx 10^(5) Sm^(-1)`


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