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A wire having length 2.0 m, diameter 1.0 mm and resistivity 1.963 10–8 m is connected in series with a battery of emf 3V and internal resistance 1. Calculate the resistance of the wire and current in the circuit. |
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Answer» Resistance, R = P l/A diameter d = 1 mm r = d/2 = 0.5 mm or r = 5 x 10-4 m R = 1.963 x 10-8 x \(\frac2{\pi(5\times10^{-4})^2}\) = 1.963 x 2/25π = 0.05 π Current, i = E/r+R = 3/1+0.05 A = 2.86 A |
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