1.

A wire in which 8 A current is flowing is kept in a uniform magnetic field 0.15 T and makes an angle 30° with the field. Calculate the magnitude of force and direction which is acting on unit length.

Answer»

Current flowing through wire I = 8 A
Magnetic field B = 0.15 T
θ = 30°
∴ Force acting on current carrying wire
F = I/B sinθ
Here l = 1 m, then force acting on unit length
F = \(\frac{F}{l}\) = 8 × 0.15 × sin30°
F = 8 × 0.15 × \(\frac{1}{2}\)
F = 0.6 N/m


Discussion

No Comment Found

Related InterviewSolutions