A wire is loaded by a weight of density `9g//cm^(3)` and stretched to a length of 98 cm. On immersing the weight in water the length shortens by 2.5 mm. Then the original length of the wire will be `[rho_(w)=1 gm//cm^(3)]`A. 95.75 cmB. 98.75 cmC. 90. 75 cmD. 85.75 cm

A wire is loaded by a weight of density `9g//cm^(3)` and stretched to

1.	A wire is loaded by a weight of density `9g//cm^(3)` and stretched to a length of 98 cm. On immersing the weight in water the length shortens by 2.5 mm. Then the original length of the wire will be `[rho_(w)=1 gm//cm^(3)]`A. 95.75 cmB. 98.75 cmC. 90. 75 cmD. 85.75 cm
Answer» Correct Answer - A `L+X=98 " " therefore x=98-L` `L+y=98-0.25 " " therefore y=98-L-0.25` `T_(1) prop x and T_(2) prop y` `(T_(1)-T_(2))/(T_(1))=(x-y)/(x)=(0.25)/(98-L)` `(V rho g)/(V rho_(1)g)=(0.25)/(98-L)` `(rho)/(rho_(1))=(0.25)/(98-L)`

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A wire is loaded by a weight of density `9g//cm^(3)` and stretched to a length of 98 cm. On immersing the weight in water the length shortens by 2.5 mm. Then the original length of the wire will be `[rho_(w)=1 gm//cm^(3)]`A. 95.75 cmB. 98.75 cmC. 90. 75 cmD. 85.75 cm

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