

InterviewSolution
Saved Bookmarks
1. |
A wire is of lengths `l_(1)` and `l_(2)` when stretched by a force 4 N and 5 N respectively. Then the length of the wire when stretched by a force 7 N will beA. `3l_(2)-2l_(1)`B. `2l_(1)-3l_(2)`C. `7l_(1)-5l_(2)`D. `5l_(1)-9l_(2)` |
Answer» Correct Answer - A For first and second tension, `L=(T_(2)l_(1)-T_(1)l_(2))/(T_(2)-T_(1))=(5l_(1)-4l_(2))/(5-4)` `=5l_(1)-4l_(2) " " ` …(i) For first and third tension, `L=(T_(3)l_(2)-T_(1)l_(3))/(T_(3)-T_(1))=(7l_(1)-4l_(3))/(7-4)` `=(7l_(1)-4l_(3))/(3) " " ` ...(ii) From equation (I) and (ii), `5l_(1)-4l_(2)=(7l_(1)-4l_(3))/(3)` `15l_(1)-12l_(2)=7l_(1)-4l_(3)` `8l_(1)-12l_(2)=-4l_(3)` `3l_(2)-2l_(1)=l_(3).` |
|