1.

A wire is stretched by `2xx10^(-2)`m due to the force of 10 N. Then the amount of work done to stretch the wire to a displacement of `4xx10^(-2)`m isA. 0.04 JB. 0.4 JC. 40 JD. 400 J

Answer» Correct Answer - B
`W_(1) =(1)/(2) Fl=(1)/(2)xx10 xx 2 xx 10^(-2) =0.1J`
`(W_(2))/(W_(1))=((l_(2))/(l_(1)))^(2)=((4xx10^(-2))/(2xx10^(-2)))^(2)=4`
`W_(2)=4W_(1)`
`=4xx0.1=0.4J`.


Discussion

No Comment Found

Related InterviewSolutions