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A wire is stretched by `2xx10^(-2)`m due to the force of 10 N. Then the amount of work done to stretch the wire to a displacement of `4xx10^(-2)`m isA. 0.04 JB. 0.4 JC. 40 JD. 400 J |
Answer» Correct Answer - B `W_(1) =(1)/(2) Fl=(1)/(2)xx10 xx 2 xx 10^(-2) =0.1J` `(W_(2))/(W_(1))=((l_(2))/(l_(1)))^(2)=((4xx10^(-2))/(2xx10^(-2)))^(2)=4` `W_(2)=4W_(1)` `=4xx0.1=0.4J`. |
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