1.

A wire is suspended from the ceiling and stretched under the action of a weight F suspended from its other end. The force exerted by the ceiling on it is equal and opposite to the weight.

Answer»

Tensile stress at any cross section A of the wire is `F/A`
Tensile stress at any cross section is zero.
Tensile stress at any cross section A of the wire is `(2F)/(A)`
TENSION at any cross section A of the wire is F.

Solution :At every cross section for the wires SUSPENDED from CEILING force exerted is F.
Now Stress = `("Tensile force ")/("Area") = F/A`
`THEREFORE` Tensile force T = Force F exerted.


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