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A wire length `6.28m` is bent into a circular coil of 2 turns. If a current of `0.5A` exists in the coil, the magnetic moment of the coil is, in `Am^(2) :`A. `(pi)/(4)`B. `(1)/(4)`C. `pi`D. `4pi` |
Answer» Correct Answer - 1 `M=NIpir^(2),l=(2pir)N` |
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