1.

A wire of density 9 xx 10^(3) kg//m^(3) is stretched between two clamps1m apart and is stretched to an extension of 4.9 xx 10^(-4) m. Young's modulus of material is 9 xx 10^(10) N//m^(2).

Answer»

The lowest frequency of STANDING wave is `35 Hz`
The frequency of `1 st` overtone is `70 Hz`
The frequency of `1 st` overtone is `105 Hz`
The STRESS in the wire is `4.41 XX 10^(7) N//m^(2)`

Solution :Speed of wave in wire
`V = sqrt((T)/(rho A)) = sqrt(( Y Delta l)/( l) A xx (1)/( rho A)) = sqrt(( Y Delta l)/( l rho))`
Maximum frequency , that means fundamental MODE .
` f = (V)/(lambda) = (V)/(2 l) = (1)/( 2l) sqrt((Y Delta l)/( l rho)) = 35 Hz`
Stress ` = Y (Delta l)/( l)`
`= 9 xx 10^(10) xx (4.9 xx 10^(-4))/( 1)`
`= 4.41 xx 10^(7) N//m^(2)`
and frequency of first overtone ` = 70 Hz`.


Discussion

No Comment Found