1.

A wire of length 1 m moves with a speed of 10 ms-1 perpendicular to a magnetic field. If the emf induced in the wire is 1 V, the magnitude of the field is-(a) 0.01 T (b) 0.1 T (c) 0.2 T (d) 0.02 T

Answer»

(b) 0.1 T

ε = Blv 

⇒ B =\(\frac{ε}{lv}\)\(\frac{1}{1 \times 10}\) = 0.02 T



Discussion

No Comment Found

Related InterviewSolutions