

InterviewSolution
Saved Bookmarks
1. |
A wire of length `50 cm` and cross sectional area of 1 sq. mm is extended by `1mm`. The required work will be `(Y=2xx10^(10) Nm^(-2))`A. `6xx10^(-2) J`B. `4xx10^(-2) J`C. `2xx10^(-2) J`D. `1 xx10^(-2) J` |
Answer» Correct Answer - C (c) Required work `W=(Yal^(2))/(2L)` `=(2xx10^(10)xx10^(-6)xx(10^(-3))^(2))/(2xx50xx10^(-2))` `=2xx10^(-2) J` |
|