A wire of length L and mass per unit length 6.0×10−3 kgm−1 is put under tension of 540 N. Two consecutive frequencies that resonates with it are : 420 Hz and 490 Hz. Then the value of L (in meters) is:

A wire of length L and mass per unit length 6.0×10−3 kgm−1 is put

1.	A wire of length L and mass per unit length 6.0×10−3 kgm−1 is put under tension of 540 N. Two consecutive frequencies that resonates with it are : 420 Hz and 490 Hz. Then the value of L (in meters) is:
Answer» A wire of length $L$ and mass per unit length $6.0 \times 10^{- 3} {kgm}^{- 1}$ is put under tension of $540 N$ . Two consecutive frequencies that resonates with it are : $420 Hz$ and $490 Hz$ . Then the value of $L$ (in meters) is:

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A wire of length L and mass per unit length 6.0×10−3 kgm−1 is put under tension of 540 N. Two consecutive frequencies that resonates with it are : 420 Hz and 490 Hz. Then the value of L (in meters) is:

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