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A wire of length l, carrying current i, is bent in circle of radius r, then magnetic moment at centre of loop isA. `Il^(2)//2pi`B. `Il^(2)//4pi`C. ID. l |
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Answer» Correct Answer - B `M=IA=Ipir^(2),Now l=2pir therefore r=(1)/(2pi)` Thus ,`M=(Ipir^(2))/(4pi^(2))=(Il^(2))/(4pi)` |
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