1.

A wire of length l, carrying current i, is bent in circle of radius r, then magnetic moment at centre of loop isA. `Il^(2)//2pi`B. `Il^(2)//4pi`C. ID. l

Answer» Correct Answer - B
`M=IA=Ipir^(2),Now l=2pir therefore r=(1)/(2pi)`
Thus ,`M=(Ipir^(2))/(4pi^(2))=(Il^(2))/(4pi)`


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