A wire of resistance `4 Omega` is stretched to four times of its original length resistance of wire now becomesA. `4Omega`B. `8Omega`C. `64Omega`D. `16Omega`

A wire of resistance `4 Omega` is stretched to four times of its origi

1.	A wire of resistance `4 Omega` is stretched to four times of its original length resistance of wire now becomesA. `4Omega`B. `8Omega`C. `64Omega`D. `16Omega`
Answer» Correct Answer - C `R_(1)=4 Omega, l_(2)=4 l_(1), R_(2)=?` `(R_(2))/(R_(1))=((l_(2))/(l_(1)))^(2)` `:.R_(2)=((4l_(1))/(l_(1)))^(2)xxR_(1)=16xx4=64Omega`.

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