A wire of resistance `5.0 Omega` is used to wind a coil of radius 5 cm. The wire has a diameter 2.0 mm and the specific resistance of its material is `2.0xx10^(-7)Omega m`. Find the number of turns in the coil.

A wire of resistance `5.0 Omega` is used to wind a coil of radius 5 cm

1.	A wire of resistance `5.0 Omega` is used to wind a coil of radius 5 cm. The wire has a diameter 2.0 mm and the specific resistance of its material is `2.0xx10^(-7)Omega m`. Find the number of turns in the coil.
Answer» Here, `R=5.0 Omega , r_(1) =5 xx10^(-2)m`, `D=2.0xx10^(-3) m, rho =2.0xx10^(-7)Omega m`. `R=rho l/(pi D^(2)//4)` or `l=(R pi D^(2))/(4 rho)` Let n be the number of turns in the coil. Then total length of the wire used, `l= 2 pi r_(1) n` or `n=l/2pi r_(1) = (R pi D^(2))/( 4 rho xx 2pi r_(1))=(R D^(2))/ (8 rho r_(1))` `=(5.0 xx (2.0xx10^(- 3))^(2))/(8xx(2.0xx10^(-7)) xx(5xx10^(-2)))=250`

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A wire of resistance `5.0 Omega` is used to wind a coil of radius 5 cm. The wire has a diameter 2.0 mm and the specific resistance of its material is `2.0xx10^(-7)Omega m`. Find the number of turns in the coil.

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