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A wire suspended vertically from one end is stretched by attaching a weight of 20 N to the lower end. The weight stretches the wire by 1 mm. How much energy is gained by the wire ?A. 0.01 JB. 0.02 JC. 0.04 JD. 1 J

Answer» Correct Answer - A
`W=(1)/(2) f xx l=(1)/(2) xx 20 xx 10^(-3)`
`=0.01J`.


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