

InterviewSolution
Saved Bookmarks
1. |
A wire suspended vertically from one of itsends is strached by attached a weight of `200 N` to the lower end . The weight streches the wire by `1 mm` . Then the elastic energy stored in the wire isA. 0.1 JB. 0.2 JC. 10 JD. 20 J |
Answer» Correct Answer - B (b) Energy stored by the spring `U=(F^(2))/(2k)=(T^(2))/(2k)` |
|