1.

A wire suspended vertically from one of itsends is strached by attached a weight of `200 N` to the lower end . The weight streches the wire by `1 mm` . Then the elastic energy stored in the wire isA. 0.1 JB. 0.2 JC. 10 JD. 20 J

Answer» Correct Answer - B
(b) Energy stored by the spring
`U=(F^(2))/(2k)=(T^(2))/(2k)`


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