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A wire suspended vertically from one of the its ends is stretched by attaching a weight of 200 N to the lower end. The weight stretches the wire by 1 mm. then the elastic energy stored in the wire isA. 0.2 JB. 10 JC. 20 jD. 0.1 J |
Answer» Correct Answer - d Elastic energy stored in the wire is `U =( 1)/(2) xx` stress `xx` strain `xx` volume `= (1)/(2) xx (F)/(A) xx (Delta l)/(l) xx Al = (1)/(2) F Delta l` or `U = (1)/(2) xx 200 xx 1 xx 10^(-3) = 0.1 J` |
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