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A wire `(Y=1xx10^(11)N//m)` has length 1m and area `1mm^(2)`. The work required to increase its length by 2mm isA. 0.4 JB. 0.8 JC. 4 JD. 400 J |
Answer» Correct Answer - A `W=(1)/(2)F l=(1)/(2) xx (Al^(2))/(L)` `=(1)/(2) xx (2xx10^(11) xx 10^(-6) xx 4 xx 10^(-6))/(1) =0.4J`. |
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