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A wooden cylinder of mass 20 g and area of cross-section `1 cm^(2)` , having a piece of lead of mass 60g attached to its bottom,floates in water. The cylinder is depressed and then released.The frequency of oxdillations is `( N )/(pi ) S^(-1)`. Find the value of N. [Neglect the volume of water displaced by the lead piece, take `g =9.8m//s^(2) `,density of water `rho_(w ) = 1 g cm^(-3) ` ] |
Answer» Correct Answer - 0.557 Hz |
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