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(a) Write the expression for the equivalent magnetic moment of a planer current loop of area A, having N turns and carrying a current i. Use the expression to find the magnetic dipole moment of a revolving electron.(b) A circular loop of radius r, having N turns and carrying current I, is kept in the XY plane. It is then subjected to a uniform magnetic field B = Bx i + By j + Bz k. Obtain expression for the magnetic potential energy of the coil-magnetic field system. |
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Answer» (a) The equivalent magnetic moment is given by μ = NiA The direction of μ is perpendicular to the plane of current carrying loop. It is directed along the direction of advance of a right-handed screw rotated along the direction of flow of current derivation of expression for μ of electron revolving around a nucleus (b) for the loop, μ = N (π r2) i (±k) Magnetic potential energy = μ.B = N (π r2) i (±k).( Bx i + By j + Bz k) = ±π r2 N I Bz |
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