1.

A1.5 kg block is initially at rest on a horizontal frictionless surface when a horizontal force in the positive direction of initial position of the block is x-0.

Answer»


SOLUTION :(a) `K =W =Wint Fdx =int_(0)^(2)(2.5-x^(2))dx`
`=2.33 J `
(b) Maximum kinetic energy of the block is at a point where FORCE changes its direction.
or `F=0`
at `X=sqrt(2.5)`
`=1.58 m`
`:. K_(max) =int_(0)^(1.58)(2.5-X^(2))dx`
`:. =2.635 J`


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