∣∣∣∣a1b1c1a2b2c2a3b3c3∣∣∣∣=5,then the value of∣∣∣∣b2c3−b3c2a3c2−a2c3a2b3−a3b2b3c1−b1c3a1c3−a3c1a3b1−a1b3b1c2−b2c1a2c1−a1c2a1b2−a2b1∣∣∣∣ is

∣∣∣∣a1b1c1a2b2c2a3b3c3∣∣∣∣=5,then the value of∣∣�

1.	∣∣∣∣a1b1c1a2b2c2a3b3c3∣∣∣∣=5,then the value of∣∣∣∣b2c3−b3c2a3c2−a2c3a2b3−a3b2b3c1−b1c3a1c3−a3c1a3b1−a1b3b1c2−b2c1a2c1−a1c2a1b2−a2b1∣∣∣∣ is
Answer» $∣ ∣∣ ∣ \begin{matrix} a_{1} & b_{1} & c_{1} a_{2} & b_{2} & c_{2} a_{3} & b_{3} & c_{3} \end{matrix} ∣ ∣∣ ∣ = 5, t h e n t h e v a l u e o f ∣ ∣∣ ∣ \begin{matrix} b_{2} c_{3} - b_{3} c_{2} & a_{3} c_{2} - a_{2} c_{3} & a_{2} b_{3} - a_{3} b_{2} b_{3} c_{1} - b_{1} c_{3} & a_{1} c_{3} - a_{3} c_{1} & a_{3} b_{1} - a_{1} b_{3} b_{1} c_{2} - b_{2} c_{1} & a_{2} c_{1} - a_{1} c_{2} & a_{1} b_{2} - a_{2} b_{1} \end{matrix} ∣ ∣∣ ∣ i s$