a2+bc+ab+ac =? A. (a + b) (a + c) B. (a + b) (b + c) C. (b + c) (c

1.	a2+bc+ab+ac =? A. (a + b) (a + c) B. (a + b) (b + c) C. (b + c) (c + a) D. a(a + b + c)
Answer» a²+bc+ab+ac = a²+ab + bc + ac Rearranging the terms and taking a and c as common respectively. = a(a + b) + c(a + b) = (a + c)(a + b).

a2+bc+ab+ac =? A. (a + b) (a + c) B. (a + b) (b + c) C. (b + c) (c + a) D. a(a + b + c)

Answer»

a²+bc+ab+ac = a²+ab + bc + ac

Rearranging the terms and taking a and c as common respectively.

= a(a + b) + c(a + b)

= (a + c)(a + b).