\ Aat n’rgi'& 1 am th gemh 5 2० bl !W8S 95— Sx +6 omd कर क

1.	\ Aat n’rgi'& 1 am th gemh 5 2० bl !W8S 95— Sx +6 omd कर कै eश्र 6० Qpe}icionts
Answer» We have polynomial p (x) =x^3- 2x^2 - 5x+ 6 So two verify 3 , -2 and 1 are zeros of our given cubic polynomial , we check As : Atx = 3 we get p ( 3) = ( 3 )^3- 2 ( 3 )^2 - 5( 3 ) + 6 p ( 3) = 27 - 18 -15 + 6 p ( 3) = 0 SO 3 is a zeros of our given polynomial . Now Atx = - 2 we get p ( -2) = ( -2 )^3- 2 ( -2 )^2 - 5( -2 ) + 6 p ( -2 ) = -8 - 8 + 10 + 6 p ( -2 ) = 0 SO -2 is a zeros of our given polynomialNow Atx = 1 we get p ( 1 ) = ( 1 )^3- 2 ( 1 )^2 - 5( 1 ) + 6 p ( 1) = 1 - 2 -5 + 6 p ( 1 ) = 0 SO 1 is a zeros of our given polynomial . So it is verified that 3 , -2 and 1 are zeros of given polynomial .

\ Aat n’rgi'& 1 am th gemh 5 2० bl !W8S 95— Sx +6 omd कर कै eश्र 6० Qpe}icionts

Answer»

We have polynomial p (x) =x^3- 2x^2 - 5x+ 6

So two verify 3 , -2 and 1 are zeros of our given cubic polynomial , we check As :

Atx = 3 we get

p ( 3) = ( 3 )^3- 2 ( 3 )^2 - 5( 3 ) + 6

p ( 3) = 27 - 18 -15 + 6

p ( 3) = 0

SO 3 is a zeros of our given polynomial .

Now Atx = - 2 we get

p ( -2) = ( -2 )^3- 2 ( -2 )^2 - 5( -2 ) + 6

p ( -2 ) = -8 - 8 + 10 + 6

p ( -2 ) = 0

SO -2 is a zeros of our given polynomialNow Atx = 1 we get

p ( 1 ) = ( 1 )^3- 2 ( 1 )^2 - 5( 1 ) + 6

p ( 1) = 1 - 2 -5 + 6

p ( 1 ) = 0

SO 1 is a zeros of our given polynomial .

So it is verified that 3 , -2 and 1 are zeros of given polynomial .